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I have some question to design the IC tps40210

I use the “SwitcherPro Desktop”software to design .

My  Vin=23~25  Vout=27V  IOUT=0.1A

I have  different  resistance from 105 mR  to  100mR (R13)

MY  Loads  is  double  12v’s  battery.

My  circuit  as  below

 

My  Vout  will  connet to  24v  battery to support battery electrify.

When I no connect the battery (NO LOAD).

My  Vin  is  24V , Vout  is   27v ( red wire),Iout is 0A(blue wire) .  as below . 

It’s OK.

But when I connect the battery . (Connect LOAD)

My  Vout  from 27 down to 24.4v and the IOUT (OUT CURRENT) have a 1.1A, 1.16ms.

The  current ‘s  distance about 700mS

As below two photo.

I want to know what’s happen?

How  can I  let  my  circuit  Vout=27v Iout=0.1A when I connect the load?

Thanks!

 

Trevor:

Jane,

    输出电压为24.4V,输出电流为1.1A,主要是因为所接负载:电池的特性所决定的,TPS40210相当于一个充电器,对

电池进行快速充电。如果希望输出27V 0.1A,可以使用电子负载来验证。

Johnsin Tao:

回复 Trevor:

如果你是要给电池充电,您需要采用电池充电芯片,例如BQ24620: www.ti.com.cn/…/bq24620.pdf,  

wu jane:

回复 wei wang1:

謝謝大家的回答!!

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