TI中文支持网在技术指南上说最大电压矢量USER_MAX_VS_MAG_PU可取1.0（理想正弦波）、2/sqrt(3)（准正弦波）以及4/3（梯形波）。但是在例程中，却说USER_MAX_VS_MAG_PU可取0.5（理想正弦波）、1/sqrt(3)（准正弦波）以及2/3（梯形波），请问这是怎么回事哇？
//! \brief Defines the maximum Voltage vector (Vs) magnitude allowed. This value sets the maximum magnitude for the output of the
//! \brief Id and Iq PI current controllers. The Id and Iq current controller outputs are Vd and Vq.
//! \brief The relationship between Vs, Vd, and Vq is: Vs = sqrt(Vd^2 + Vq^2). In this FOC controller, the
//! \brief Vd value is set equal to USER_MAX_VS_MAG*USER_VD_MAG_FACTOR. Vq = sqrt(USER_MAX_VS_MAG^2 – Vd^2).
//! \brief Set USER_MAX_VS_MAG = 0.5 for a pure sinewave with a peak at SQRT(3)/2 = 86.6% duty cycle. No current reconstruction is needed for this scenario.
//! \brief Set USER_MAX_VS_MAG = 1/SQRT(3) = 0.5774 for a pure sinewave with a peak at 100% duty cycle. Current reconstruction will be needed for this scenario (Lab10a-x).
//! \brief Set USER_MAX_VS_MAG = 2/3 = 0.6666 to create a trapezoidal voltage waveform. Current reconstruction will be needed for this scenario (Lab10a-x).
//! \brief For space vector over-modulation, see lab 10 for details on system requirements that will allow the SVM generator to go all the way to trapezoidal.
#define USER_MAX_VS_MAG_PU (0.5) // Set to 0.5 if a current reconstruction technique is not used. Look at the module svgen_current in lab10a-x for more info.
