TI中文支持网采集的是一个正弦波，通过数组Voltage1来观察数据和波形。但是采样值基本无变化，这是为什么呢？下面附上程序：
主函数：
void main(void)
{EALLOW;SysCtrlRegs.HISPCP.all = ADC_MODCLK; // HSPCLK = SYSCLKOUT/2*ADC_MODCLKEDIS;
int i;
InitSysCtrl();//初始化系统函数
IER = 0x0000;//禁止CPU中断IFR = 0x0000;//清除CPU中断标志InitPieCtrl();//初始化PIE控制寄存器InitPieVectTable();//初始化PIE中断向量表
InitCpuTimers();InitEPwm1Gpio();InitEPwm2Gpio();InitEPwm3Gpio();DINT;InitAdc();//ADC初始化EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 0;//禁止PWM时钟EDIS;InitEPwm1Example();InitEPwm2Example();InitEPwm3Example();ConfigCpuTimer(&CpuTimer0,30,1000);StartCpuTimer0();//启动定时器0PieCtrlRegs.PIECTRL.bit.ENPIE = 1;//使能PIE模块的总中断EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 1;//使能PWM时钟EDIS;EALLOW; // This is needed to write to EALLOW protected registerPieVectTable.TINT0 = &TINT0_ISR;//使能Timer0中断PieVectTable.ADCINT = &ADCINT_ISR;//使能ADC中断EDIS;// This is needed to disable write to EALLOW protected registersPieCtrlRegs.PIEIER1.bit.INTx7 = 1; //使能PIE中断的CPU定时器0PieCtrlRegs.PIEIER1.bit.INTx6 = 1; //使能PIE中断中的ADC中断IER |= (M_INT1); // Enable CPU Interrupt 1EINT;//使能全局中断ERTM;//使能实时中断
for (i=0; i<BUF_SIZE; i++){Voltage1[i] = 0;Voltage2[i] = 0;Voltage3[i] = 0;}
定时器中断函数：
Uint16 q=0;
interrupt void TINT0_ISR(void)// CPU-Timer 0
{// Insert ISR Code hereq++;//判断是否进入中断
AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;//软件触发启动SEQ1PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
ADC中断函数：
Uint16 qa=0;
interrupt void ADCINT_ISR(void) // ADC
{
// Insert ISR Code here
qa++;//判断是否进入中断
// To receive more interrupts from this PIE group, acknowledge this interrupt // PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Next two lines for debug only to halt the processor here
// Remove after inserting ISR Code
Uint16 a[10],b[10],c[10];
Uint16 i,j,r,s,t;
Voltage1[ConversionCount1++] = AdcRegs.ADCRESULT0 >>4;
Voltage2[ConversionCount2++] = AdcRegs.ADCRESULT1 >>4;
Voltage3[ConversionCount3++] = AdcRegs.ADCRESULT2 >>4;
if(ConversionCount1>(511))
ConversionCount1=0;
DELAY_US(100);
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1; // Reset SEQ1
AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1; // Clear INT SEQ1 bit
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Acknowledge interrupt to PIE
ADC初始化函数：
extern void DSP28x_usDelay(Uint32 Count);EALLOW;
SysCtrlRegs.PCLKCR0.bit.ADCENCLK = 1;//使能ADC时钟
ADC_cal();
EDIS;
AdcRegs.ADCTRL1.bit.RESET = 1;//Reset ADC moduleasm(" RPT #20||NOP");AdcRegs.ADCTRL3.all = 0x00E0; // 给ADC内部上电DELAY_US(ADC_usDELAY);// 在ADC转换前要延时一段时间
AdcRegs.ADCTRL1.bit.ACQ_PS = 0xff; // Sequential mode: Sample rate= 1/[(2+ACQ_PS)*ADC clock in ns]//= 1/(3*40ns) =8.3MHz (for 150 MHz SYSCLKOUT)//= 1/(3*80ns) =4.17MHz (for 100 MHz SYSCLKOUT)// If Simultaneous mode enabled: Sample rate = 1/[(3+ACQ_PS)*ADC clock in ns]AdcRegs.ADCTRL3.bit.ADCCLKPS = 0;//不分频AdcRegs.ADCTRL1.bit.SEQ_CASC = 1;// 1 Cascaded modeAdcRegs.ADCTRL1.bit.CONT_RUN = 1;// Setup continuous runAdcRegs.ADCTRL1.bit.SEQ_OVRD = 1;// Enable Sequencer override featureAdcRegs.ADCMAXCONV.bit.MAX_CONV1 = 0x2; // convert and store in 8 results registersAdcRegs.ADCCHSELSEQ1.bit.CONV00 = 0x0; // Setup ADCINA3 as 1st SEQ1 conv.AdcRegs.ADCCHSELSEQ1.bit.CONV01 = 0x1;AdcRegs.ADCCHSELSEQ1.bit.CONV02 = 0x2;// Setup ADCINA2 as 2nd SEQ1 conv.AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1; // 向CPU发出中断申请
这个问题已经困扰我好几天了，实在是没检查出来是什么问题，希望看到的大神停下来帮忙指点一下，感激不尽！！！
likai hu：
代码有点多。。但是思路还是挺清晰的，求大神们帮忙看看！！！！
采集的是一个正弦波，通过数组Voltage1来观察数据和波形。但是采样值基本无变化，这是为什么呢？下面附上程序：
主函数：
void main(void)
{EALLOW;SysCtrlRegs.HISPCP.all = ADC_MODCLK; // HSPCLK = SYSCLKOUT/2*ADC_MODCLKEDIS;
int i;
InitSysCtrl();//初始化系统函数
IER = 0x0000;//禁止CPU中断IFR = 0x0000;//清除CPU中断标志InitPieCtrl();//初始化PIE控制寄存器InitPieVectTable();//初始化PIE中断向量表
InitCpuTimers();InitEPwm1Gpio();InitEPwm2Gpio();InitEPwm3Gpio();DINT;InitAdc();//ADC初始化EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 0;//禁止PWM时钟EDIS;InitEPwm1Example();InitEPwm2Example();InitEPwm3Example();ConfigCpuTimer(&CpuTimer0,30,1000);StartCpuTimer0();//启动定时器0PieCtrlRegs.PIECTRL.bit.ENPIE = 1;//使能PIE模块的总中断EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 1;//使能PWM时钟EDIS;EALLOW; // This is needed to write to EALLOW protected registerPieVectTable.TINT0 = &TINT0_ISR;//使能Timer0中断PieVectTable.ADCINT = &ADCINT_ISR;//使能ADC中断EDIS;// This is needed to disable write to EALLOW protected registersPieCtrlRegs.PIEIER1.bit.INTx7 = 1; //使能PIE中断的CPU定时器0PieCtrlRegs.PIEIER1.bit.INTx6 = 1; //使能PIE中断中的ADC中断IER |= (M_INT1); // Enable CPU Interrupt 1EINT;//使能全局中断ERTM;//使能实时中断
for (i=0; i<BUF_SIZE; i++){Voltage1[i] = 0;Voltage2[i] = 0;Voltage3[i] = 0;}
定时器中断函数：
Uint16 q=0;
interrupt void TINT0_ISR(void)// CPU-Timer 0
{// Insert ISR Code hereq++;//判断是否进入中断
AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;//软件触发启动SEQ1PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
ADC中断函数：
Uint16 qa=0;
interrupt void ADCINT_ISR(void) // ADC
{
// Insert ISR Code here
qa++;//判断是否进入中断
// To receive more interrupts from this PIE group, acknowledge this interrupt // PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Next two lines for debug only to halt the processor here
// Remove after inserting ISR Code
Uint16 a[10],b[10],c[10];
Uint16 i,j,r,s,t;
Voltage1[ConversionCount1++] = AdcRegs.ADCRESULT0 >>4;
Voltage2[ConversionCount2++] = AdcRegs.ADCRESULT1 >>4;
Voltage3[ConversionCount3++] = AdcRegs.ADCRESULT2 >>4;
if(ConversionCount1>(511))
ConversionCount1=0;
DELAY_US(100);
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1; // Reset SEQ1
AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1; // Clear INT SEQ1 bit
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Acknowledge interrupt to PIE
ADC初始化函数：
extern void DSP28x_usDelay(Uint32 Count);EALLOW;
SysCtrlRegs.PCLKCR0.bit.ADCENCLK = 1;//使能ADC时钟
ADC_cal();
EDIS;
AdcRegs.ADCTRL1.bit.RESET = 1;//Reset ADC moduleasm(" RPT #20||NOP");AdcRegs.ADCTRL3.all = 0x00E0; // 给ADC内部上电DELAY_US(ADC_usDELAY);// 在ADC转换前要延时一段时间
AdcRegs.ADCTRL1.bit.ACQ_PS = 0xff; // Sequential mode: Sample rate= 1/[(2+ACQ_PS)*ADC clock in ns]//= 1/(3*40ns) =8.3MHz (for 150 MHz SYSCLKOUT)//= 1/(3*80ns) =4.17MHz (for 100 MHz SYSCLKOUT)// If Simultaneous mode enabled: Sample rate = 1/[(3+ACQ_PS)*ADC clock in ns]AdcRegs.ADCTRL3.bit.ADCCLKPS = 0;//不分频AdcRegs.ADCTRL1.bit.SEQ_CASC = 1;// 1 Cascaded modeAdcRegs.ADCTRL1.bit.CONT_RUN = 1;// Setup continuous runAdcRegs.ADCTRL1.bit.SEQ_OVRD = 1;// Enable Sequencer override featureAdcRegs.ADCMAXCONV.bit.MAX_CONV1 = 0x2; // convert and store in 8 results registersAdcRegs.ADCCHSELSEQ1.bit.CONV00 = 0x0; // Setup ADCINA3 as 1st SEQ1 conv.AdcRegs.ADCCHSELSEQ1.bit.CONV01 = 0x1;AdcRegs.ADCCHSELSEQ1.bit.CONV02 = 0x2;// Setup ADCINA2 as 2nd SEQ1 conv.AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1; // 向CPU发出中断申请
这个问题已经困扰我好几天了，实在是没检查出来是什么问题，希望看到的大神停下来帮忙指点一下，感激不尽！！！
Eric Ma：
回复 likai hu:
ERIC:
你在CCS的register窗口上查看ADC的结果寄存器，看它有没有变化。
另外，用TI的例程进行对比测试，排查：
C:\ti\controlSUITE\device_support\f2833x\v142\DSP2833x_examples_ccsv5\adc_soc
采集的是一个正弦波，通过数组Voltage1来观察数据和波形。但是采样值基本无变化，这是为什么呢？下面附上程序：
主函数：
void main(void)
{EALLOW;SysCtrlRegs.HISPCP.all = ADC_MODCLK; // HSPCLK = SYSCLKOUT/2*ADC_MODCLKEDIS;
int i;
InitSysCtrl();//初始化系统函数
IER = 0x0000;//禁止CPU中断IFR = 0x0000;//清除CPU中断标志InitPieCtrl();//初始化PIE控制寄存器InitPieVectTable();//初始化PIE中断向量表
InitCpuTimers();InitEPwm1Gpio();InitEPwm2Gpio();InitEPwm3Gpio();DINT;InitAdc();//ADC初始化EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 0;//禁止PWM时钟EDIS;InitEPwm1Example();InitEPwm2Example();InitEPwm3Example();ConfigCpuTimer(&CpuTimer0,30,1000);StartCpuTimer0();//启动定时器0PieCtrlRegs.PIECTRL.bit.ENPIE = 1;//使能PIE模块的总中断EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 1;//使能PWM时钟EDIS;EALLOW; // This is needed to write to EALLOW protected registerPieVectTable.TINT0 = &TINT0_ISR;//使能Timer0中断PieVectTable.ADCINT = &ADCINT_ISR;//使能ADC中断EDIS;// This is needed to disable write to EALLOW protected registersPieCtrlRegs.PIEIER1.bit.INTx7 = 1; //使能PIE中断的CPU定时器0PieCtrlRegs.PIEIER1.bit.INTx6 = 1; //使能PIE中断中的ADC中断IER |= (M_INT1); // Enable CPU Interrupt 1EINT;//使能全局中断ERTM;//使能实时中断
for (i=0; i<BUF_SIZE; i++){Voltage1[i] = 0;Voltage2[i] = 0;Voltage3[i] = 0;}
定时器中断函数：
Uint16 q=0;
interrupt void TINT0_ISR(void)// CPU-Timer 0
{// Insert ISR Code hereq++;//判断是否进入中断
AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;//软件触发启动SEQ1PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
ADC中断函数：
Uint16 qa=0;
interrupt void ADCINT_ISR(void) // ADC
{
// Insert ISR Code here
qa++;//判断是否进入中断
// To receive more interrupts from this PIE group, acknowledge this interrupt // PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Next two lines for debug only to halt the processor here
// Remove after inserting ISR Code
Uint16 a[10],b[10],c[10];
Uint16 i,j,r,s,t;
Voltage1[ConversionCount1++] = AdcRegs.ADCRESULT0 >>4;
Voltage2[ConversionCount2++] = AdcRegs.ADCRESULT1 >>4;
Voltage3[ConversionCount3++] = AdcRegs.ADCRESULT2 >>4;
if(ConversionCount1>(511))
ConversionCount1=0;
DELAY_US(100);
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1; // Reset SEQ1
AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1; // Clear INT SEQ1 bit
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Acknowledge interrupt to PIE
ADC初始化函数：
extern void DSP28x_usDelay(Uint32 Count);EALLOW;
SysCtrlRegs.PCLKCR0.bit.ADCENCLK = 1;//使能ADC时钟
ADC_cal();
EDIS;
AdcRegs.ADCTRL1.bit.RESET = 1;//Reset ADC moduleasm(" RPT #20||NOP");AdcRegs.ADCTRL3.all = 0x00E0; // 给ADC内部上电DELAY_US(ADC_usDELAY);// 在ADC转换前要延时一段时间
AdcRegs.ADCTRL1.bit.ACQ_PS = 0xff; // Sequential mode: Sample rate= 1/[(2+ACQ_PS)*ADC clock in ns]//= 1/(3*40ns) =8.3MHz (for 150 MHz SYSCLKOUT)//= 1/(3*80ns) =4.17MHz (for 100 MHz SYSCLKOUT)// If Simultaneous mode enabled: Sample rate = 1/[(3+ACQ_PS)*ADC clock in ns]AdcRegs.ADCTRL3.bit.ADCCLKPS = 0;//不分频AdcRegs.ADCTRL1.bit.SEQ_CASC = 1;// 1 Cascaded modeAdcRegs.ADCTRL1.bit.CONT_RUN = 1;// Setup continuous runAdcRegs.ADCTRL1.bit.SEQ_OVRD = 1;// Enable Sequencer override featureAdcRegs.ADCMAXCONV.bit.MAX_CONV1 = 0x2; // convert and store in 8 results registersAdcRegs.ADCCHSELSEQ1.bit.CONV00 = 0x0; // Setup ADCINA3 as 1st SEQ1 conv.AdcRegs.ADCCHSELSEQ1.bit.CONV01 = 0x1;AdcRegs.ADCCHSELSEQ1.bit.CONV02 = 0x2;// Setup ADCINA2 as 2nd SEQ1 conv.AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1; // 向CPU发出中断申请
这个问题已经困扰我好几天了，实在是没检查出来是什么问题，希望看到的大神停下来帮忙指点一下，感激不尽！！！
user5006393：请问你解决了么？请教下你
采集的是一个正弦波，通过数组Voltage1来观察数据和波形。但是采样值基本无变化，这是为什么呢？下面附上程序：
主函数：
void main(void)
{EALLOW;SysCtrlRegs.HISPCP.all = ADC_MODCLK; // HSPCLK = SYSCLKOUT/2*ADC_MODCLKEDIS;
int i;
InitSysCtrl();//初始化系统函数
IER = 0x0000;//禁止CPU中断IFR = 0x0000;//清除CPU中断标志InitPieCtrl();//初始化PIE控制寄存器InitPieVectTable();//初始化PIE中断向量表
InitCpuTimers();InitEPwm1Gpio();InitEPwm2Gpio();InitEPwm3Gpio();DINT;InitAdc();//ADC初始化EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 0;//禁止PWM时钟EDIS;InitEPwm1Example();InitEPwm2Example();InitEPwm3Example();ConfigCpuTimer(&CpuTimer0,30,1000);StartCpuTimer0();//启动定时器0PieCtrlRegs.PIECTRL.bit.ENPIE = 1;//使能PIE模块的总中断EALLOW;SysCtrlRegs.PCLKCR0.bit.TBCLKSYNC = 1;//使能PWM时钟EDIS;EALLOW; // This is needed to write to EALLOW protected registerPieVectTable.TINT0 = &TINT0_ISR;//使能Timer0中断PieVectTable.ADCINT = &ADCINT_ISR;//使能ADC中断EDIS;// This is needed to disable write to EALLOW protected registersPieCtrlRegs.PIEIER1.bit.INTx7 = 1; //使能PIE中断的CPU定时器0PieCtrlRegs.PIEIER1.bit.INTx6 = 1; //使能PIE中断中的ADC中断IER |= (M_INT1); // Enable CPU Interrupt 1EINT;//使能全局中断ERTM;//使能实时中断
for (i=0; i<BUF_SIZE; i++){Voltage1[i] = 0;Voltage2[i] = 0;Voltage3[i] = 0;}
定时器中断函数：
Uint16 q=0;
interrupt void TINT0_ISR(void)// CPU-Timer 0
{// Insert ISR Code hereq++;//判断是否进入中断
AdcRegs.ADCTRL2.bit.SOC_SEQ1 = 1;//软件触发启动SEQ1PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
ADC中断函数：
Uint16 qa=0;
interrupt void ADCINT_ISR(void) // ADC
{
// Insert ISR Code here
qa++;//判断是否进入中断
// To receive more interrupts from this PIE group, acknowledge this interrupt // PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Next two lines for debug only to halt the processor here
// Remove after inserting ISR Code
Uint16 a[10],b[10],c[10];
Uint16 i,j,r,s,t;
Voltage1[ConversionCount1++] = AdcRegs.ADCRESULT0 >>4;
Voltage2[ConversionCount2++] = AdcRegs.ADCRESULT1 >>4;
Voltage3[ConversionCount3++] = AdcRegs.ADCRESULT2 >>4;
if(ConversionCount1>(511))
ConversionCount1=0;
DELAY_US(100);
AdcRegs.ADCTRL2.bit.RST_SEQ1 = 1; // Reset SEQ1
AdcRegs.ADCST.bit.INT_SEQ1_CLR = 1; // Clear INT SEQ1 bit
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1; // Acknowledge interrupt to PIE
ADC初始化函数：
extern void DSP28x_usDelay(Uint32 Count);EALLOW;
SysCtrlRegs.PCLKCR0.bit.ADCENCLK = 1;//使能ADC时钟
ADC_cal();
EDIS;
AdcRegs.ADCTRL1.bit.RESET = 1;//Reset ADC moduleasm(" RPT #20||NOP");AdcRegs.ADCTRL3.all = 0x00E0; // 给ADC内部上电DELAY_US(ADC_usDELAY);// 在ADC转换前要延时一段时间
AdcRegs.ADCTRL1.bit.ACQ_PS = 0xff; // Sequential mode: Sample rate= 1/[(2+ACQ_PS)*ADC clock in ns]//= 1/(3*40ns) =8.3MHz (for 150 MHz SYSCLKOUT)//= 1/(3*80ns) =4.17MHz (for 100 MHz SYSCLKOUT)// If Simultaneous mode enabled: Sample rate = 1/[(3+ACQ_PS)*ADC clock in ns]AdcRegs.ADCTRL3.bit.ADCCLKPS = 0;//不分频AdcRegs.ADCTRL1.bit.SEQ_CASC = 1;// 1 Cascaded modeAdcRegs.ADCTRL1.bit.CONT_RUN = 1;// Setup continuous runAdcRegs.ADCTRL1.bit.SEQ_OVRD = 1;// Enable Sequencer override featureAdcRegs.ADCMAXCONV.bit.MAX_CONV1 = 0x2; // convert and store in 8 results registersAdcRegs.ADCCHSELSEQ1.bit.CONV00 = 0x0; // Setup ADCINA3 as 1st SEQ1 conv.AdcRegs.ADCCHSELSEQ1.bit.CONV01 = 0x1;AdcRegs.ADCCHSELSEQ1.bit.CONV02 = 0x2;// Setup ADCINA2 as 2nd SEQ1 conv.AdcRegs.ADCTRL2.bit.INT_ENA_SEQ1 = 1; // 向CPU发出中断申请
这个问题已经困扰我好几天了，实在是没检查出来是什么问题，希望看到的大神停下来帮忙指点一下，感激不尽！！！
mangui zhang：
回复 user5006393:
个人还是觉得先用TI的例程测试然后在此基础上进行修改
