MSP430G2553示例程序疑问

//******************************************************************************
// MSP430G2x33/G2x53 Demo – ADC10, Sample A1, 1.5V, TA1 Trig, Set P1.0 if > 0.5V
//
// Description: A1 is sampled 16/second (ACLK/2048) with reference to 1.5V.
// Timer_A is run in upmode and TA1 is used to automatically trigger
// ADC10 conversion, TA0 defines the period. Internal oscillator times sample
// (16x) and conversion (13x). Inside ADC10_ISR if A1 > 0.5Vcc, P1.0 is set,
// else reset. Normal mode is LPM3.
// //* An external watch crystal on XIN XOUT is required for ACLK *//
//
// MSP430G2x33/G2x53
// —————–
// /|\| XIN|-
// | | | 32kHz
// –|RST XOUT|-
// | |
// >—|P1.1/A1 P1.0 |–> LED
//
// D. Dang
// Texas Instruments Inc.
// December 2010
// Built with CCS Version 4.2.0 and IAR Embedded Workbench Version: 5.10
//******************************************************************************
#include "msp430g2553.h"

void main(void)
{
WDTCTL = WDTPW + WDTHOLD; // Stop WDT
ADC10CTL1 = SHS_1 + CONSEQ_2 + INCH_1; // TA1 trigger sample start
ADC10CTL0 = SREF_1 + ADC10SHT_2 + REFON + ADC10ON + ADC10IE;
__enable_interrupt(); // Enable interrupts.
TACCR0 = 30; // Delay to allow Ref to settle
TACCTL0 |= CCIE; // Compare-mode interrupt.
TACTL = TASSEL_2 + MC_1; // TACLK = SMCLK, Up mode.
LPM0; // Wait for delay.
TACCTL0 &= ~CCIE; // Disable timer Interrupt
__disable_interrupt();
ADC10CTL0 |= ENC; // ADC10 Enable
ADC10AE0 |= 0x02; // P1.1 ADC10 option select
P1DIR |= 0x01; // Set P1.0 output
TACCR0 = 2048-1; // PWM Period
TACCTL1 = OUTMOD_3; // TACCR1 set/reset
TACCR1 = 2047; // TACCR1 PWM Duty Cycle
TACTL = TASSEL_1 + MC_1; // ACLK, up mode

__bis_SR_register(LPM3_bits + GIE); // Enter LPM3 w/ interrupts
}

// ADC10 interrupt service routine
#pragma vector=ADC10_VECTOR
__interrupt void ADC10_ISR(void)
{
if (ADC10MEM < 0x155) // ADC10MEM = A1 > 0.5V?
P1OUT &= ~0x01; // Clear P1.0 LED off
else
P1OUT |= 0x01; // Set P1.0 LED on
}

#pragma vector=TIMER0_A0_VECTOR
__interrupt void ta0_isr(void)
{
TACTL = 0;
LPM0_EXIT; // Exit LPM0 on return
}

以上是MSP430G2553示例程序，用TimerA触发ADC10转换，我想问的是，ADC10转换没有放在TimerA中断里？就示例程序来看能成功触发ADC转换吗？

Ling Zhu2：

   你好，定时器触发ADC之后，ADC自动完成转换。

Triton Zhang：

ADC10CTL1 = SHS_1 + CONSEQ_2 + INCH_1; // TA1 trigger sample start

SHS_1就是设置TA1触发ADC，并不需要进入到TA中断处理程序。

Haiqi Bian：

回复 Triton Zhang:

追问一下，如果在这样的情况下，我把ADC写进了TA的中断函数，会发生什么样的情况呢？

Haiqi Bian：

回复 Ling Zhu2:

你好！

我想接着问一下这段函数的运行流程。1.__enable_interrupt();进入的是ADC10_VECTOR中断？2.这段代码中TIMER0_A0_VECTOR中断起到的又是什么作用？