TI中文支持网Part Number:AWR2243
中文 ： Ti的datasheet里面关于移相器写的是6位，这里是AWR2243读出目前校准的相位值，文档里圈起来的地方1 LSB是除以2^10,（理解起来应该是用精度更高位的10位来做校准），但是文档里圈起来的地方（观测的相位值被存储在两个8位字节中，那按理1 LSB应该是除以2^16，所以不是很理解是怎么校准的，对应关系是怎样的？ 请帮忙解答一下，不甚感激！
English: The Ti datasheet for phase shifter is 6 bits, here is AWR2243 read the current calibrated phase value, circled in the document 1 LSB is divided by 2^10, (understanding should be using the higher precision 10 bits to do the calibration), But circled in the document (the observed phase value is stored in two 8-bit bytes, so logically 1 LSB should be divided by 2^16, so it's not quite clear how it's calibrated, what's the correspondence? Please help to answer, I am very grateful!
Shine：
请参考您另外一个帖子的回复。https://e2echina.ti.com/support/sensors/f/sensors-forum/755446/awr2243-awr2243
