TI中文支持网Part Number:AWR2243Other Parts Discussed in Thread: AWR1843
各位TI的工程师，你们好
我们使用AWR2243的汽车雷达，需要拿到工信部的CMIIT ID，按照汽车雷达无线电管理暂行规定 工信部无〔2021〕181号里面的规定，需要满足接收机杂散限值要求
据我们了解，该测试需要获取RX接受到的经过芯片内部低通滤波处理之后，ADC之前的信号，
之前在另一个帖子里讨论过说是AWR2243是SOC方案，无法获取ADC之前的数据，
(+) AWR2243: MMWCAS-RF-EVM – 传感器论坛 – 传感器 – E2E
设计支持 (ti.com)
那么使用AW2243的产品如何获得工信部的CMIIT ID？你们是否有自己内部的杂散测试报告？或者是否有接收机杂散测试方案？
谢谢。
Shine：
我把您的问题转到e2e了，看是否有这样的报告提供。请关注下面帖子的回复。https://e2e.ti.com/support/sensors-group/sensors/f/sensors-forum/1082209/awr2243-spurious-emission-testing-report
,
Shine：
请参考下面e2e工程师的回复。
We do not have any emissions reports on AWR2243, but the emissions performance between AWR2243 and AWR1843 will be very similar. You can refer to the report for AWR1843 to reference for AWR2243.
We do not have any testing for CMIIT for any of our devices. However, we do have customers who have gone to production in China with our devices so the device likely should meet the required limits for CMIIT. I would recommend for the customer to provide a provision for a shield around the AWR2243 and surrounding decoupling capacitors as described in section 5.3 of the below app note. The shield needs to be properly grounded to the PCB around all sides to act as a faraday cage or it will make performance worse.
https://www.ti.com/lit/an/spracp3c/spracp3c.pdf
