TI中文支持网
TI专业的中文技术问题搜集分享网站
当前位置：TI中文支持网 > 微处理器 MCU > C2000™ 32位实时 MCU > 正文

关于28035中断嵌套，嵌套的中断多执行了一次

2018-10-29 分类：C2000™ 32位实时 MCU 阅读(564)

如图所示，打算使用三个中断，分别是EPWM4_ISR(90kHz),   CpuTimer_ISR(10 kHz),   EPWM1_ISR(200 kHz, 50%, Zero Trigger),  使其中EPWM4_ISR，CpuTimer_ISR 中都嵌套 EPWM1_ISR；当只 EPWM4_ISR 嵌套EPWM1_ISR 或  只CpuTimer_ISR嵌套EPWM1_ISR，EPWM1_ISR 可正常嵌套执行；但是当EPWM4_ISR，CpuTimer_ISR，同时嵌套EPWM1_ISR时出现一个问题,  EPWM1_ISR 会不时的多执行一次（图中红色箭头处）。请问为什么会这样，怎么解决这个问题？请大神指导！！！！

代码如下：
volatile Uint16 NestPIEIER;
__interrupt void epwm1_isr ( void )
{
—————————————————————–
// Update EPWM1 & EPWM2
//———————————————————————
// Clear INT flag for this timer
// Acknowledge this interrupt to receive more interrupts from group 3
//———————————————————————
EPwm1Regs.ETCLR.bit.INT = 1;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3;

}

__interrupt void epwm4_isr(void)
{ //————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//———————————————————————
// Acknowledge this interrupt to receive more interrupts from group 3
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3; ///2
// Clear INT flag for this timer
EPwm4Regs.ETCLR.bit.INT = 1; ///2

}

__interrupt void CpuTimer0_isr ( void )
{
//————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//
// Acknowledge this interrupt to receive more interrupts from group 1
//
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}

通道2（绿）：测试IO   Epwm4_isr      90kHz
通道4（红）:  测试IO   CpuTimer0_isr 10 kHz
通道1（黄）：测试IO   epwm1_isr      200KHz, 
通道3（蓝）：epwm1 outputA

mangui zhang：看波形好像与CPUTimer有关系注意中断中清除标志

如图所示，打算使用三个中断，分别是EPWM4_ISR(90kHz),   CpuTimer_ISR(10 kHz),   EPWM1_ISR(200 kHz, 50%, Zero Trigger),  使其中EPWM4_ISR，CpuTimer_ISR 中都嵌套 EPWM1_ISR；当只 EPWM4_ISR 嵌套EPWM1_ISR 或  只CpuTimer_ISR嵌套EPWM1_ISR，EPWM1_ISR 可正常嵌套执行；但是当EPWM4_ISR，CpuTimer_ISR，同时嵌套EPWM1_ISR时出现一个问题,  EPWM1_ISR 会不时的多执行一次（图中红色箭头处）。请问为什么会这样，怎么解决这个问题？请大神指导！！！！

代码如下：
volatile Uint16 NestPIEIER;
__interrupt void epwm1_isr ( void )
{
—————————————————————–
// Update EPWM1 & EPWM2
//———————————————————————
// Clear INT flag for this timer
// Acknowledge this interrupt to receive more interrupts from group 3
//———————————————————————
EPwm1Regs.ETCLR.bit.INT = 1;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3;

}

__interrupt void epwm4_isr(void)
{ //————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//———————————————————————
// Acknowledge this interrupt to receive more interrupts from group 3
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3; ///2
// Clear INT flag for this timer
EPwm4Regs.ETCLR.bit.INT = 1; ///2

}

__interrupt void CpuTimer0_isr ( void )
{
//————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//
// Acknowledge this interrupt to receive more interrupts from group 1
//
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}

通道2（绿）：测试IO   Epwm4_isr      90kHz
通道4（红）:  测试IO   CpuTimer0_isr 10 kHz
通道1（黄）：测试IO   epwm1_isr      200KHz, 
通道3（蓝）：epwm1 outputA

user5860441：把PieCtrlRegs.PIEACK.all = PIEACK_GROUP3;换成PieCtrlRegs.PIEACK.bit.ACK3 = 1;

把所有的都改一下，试试。

如图所示，打算使用三个中断，分别是EPWM4_ISR(90kHz),   CpuTimer_ISR(10 kHz),   EPWM1_ISR(200 kHz, 50%, Zero Trigger),  使其中EPWM4_ISR，CpuTimer_ISR 中都嵌套 EPWM1_ISR；当只 EPWM4_ISR 嵌套EPWM1_ISR 或  只CpuTimer_ISR嵌套EPWM1_ISR，EPWM1_ISR 可正常嵌套执行；但是当EPWM4_ISR，CpuTimer_ISR，同时嵌套EPWM1_ISR时出现一个问题,  EPWM1_ISR 会不时的多执行一次（图中红色箭头处）。请问为什么会这样，怎么解决这个问题？请大神指导！！！！

代码如下：
volatile Uint16 NestPIEIER;
__interrupt void epwm1_isr ( void )
{
—————————————————————–
// Update EPWM1 & EPWM2
//———————————————————————
// Clear INT flag for this timer
// Acknowledge this interrupt to receive more interrupts from group 3
//———————————————————————
EPwm1Regs.ETCLR.bit.INT = 1;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3;

}

__interrupt void epwm4_isr(void)
{ //————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//———————————————————————
// Acknowledge this interrupt to receive more interrupts from group 3
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3; ///2
// Clear INT flag for this timer
EPwm4Regs.ETCLR.bit.INT = 1; ///2

}

__interrupt void CpuTimer0_isr ( void )
{
//————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//
// Acknowledge this interrupt to receive more interrupts from group 1
//
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}

通道2（绿）：测试IO   Epwm4_isr      90kHz
通道4（红）:  测试IO   CpuTimer0_isr 10 kHz
通道1（黄）：测试IO   epwm1_isr      200KHz, 
通道3（蓝）：epwm1 outputA

user4828609：

回复 user5860441:

试过了，没效果

如图所示，打算使用三个中断，分别是EPWM4_ISR(90kHz),   CpuTimer_ISR(10 kHz),   EPWM1_ISR(200 kHz, 50%, Zero Trigger),  使其中EPWM4_ISR，CpuTimer_ISR 中都嵌套 EPWM1_ISR；当只 EPWM4_ISR 嵌套EPWM1_ISR 或  只CpuTimer_ISR嵌套EPWM1_ISR，EPWM1_ISR 可正常嵌套执行；但是当EPWM4_ISR，CpuTimer_ISR，同时嵌套EPWM1_ISR时出现一个问题,  EPWM1_ISR 会不时的多执行一次（图中红色箭头处）。请问为什么会这样，怎么解决这个问题？请大神指导！！！！

代码如下：
volatile Uint16 NestPIEIER;
__interrupt void epwm1_isr ( void )
{
—————————————————————–
// Update EPWM1 & EPWM2
//———————————————————————
// Clear INT flag for this timer
// Acknowledge this interrupt to receive more interrupts from group 3
//———————————————————————
EPwm1Regs.ETCLR.bit.INT = 1;
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3;

}

__interrupt void epwm4_isr(void)
{ //————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//———————————————————————
// Acknowledge this interrupt to receive more interrupts from group 3
PieCtrlRegs.PIEACK.all = PIEACK_GROUP3; ///2
// Clear INT flag for this timer
EPwm4Regs.ETCLR.bit.INT = 1; ///2

}

__interrupt void CpuTimer0_isr ( void )
{
//————————————————————-
// Set interrupt priority:
NestPIEIER = PieCtrlRegs.PIEIER3.all;
IER |= M_INT3;
IER &= M_INT3; // Set "global" priority
PieCtrlRegs.PIEIER3.all &= 0x0001; // Set "group" priority
PieCtrlRegs.PIEACK.all = 0xFFFF; // Enable PIE interrupts
__asm(" NOP");
EINT;
//———————————————————
// Insert ISR Code here…….
//———————————————————
//———————————————————————
// Restore registers saved:
DINT;
PieCtrlRegs.PIEIER3.all = NestPIEIER;
//
// Acknowledge this interrupt to receive more interrupts from group 1
//
PieCtrlRegs.PIEACK.all = PIEACK_GROUP1;
}

通道2（绿）：测试IO   Epwm4_isr      90kHz
通道4（红）:  测试IO   CpuTimer0_isr 10 kHz
通道1（黄）：测试IO   epwm1_isr      200KHz, 
通道3（蓝）：epwm1 outputA

Li Robert：根據波形，懷疑是Timer0的中斷觸發epwm1，所以當進入Timer0打開中斷後直接跳epwm1中斷。
可以把Timer0換成Timer1/2看能否避掉此問題

赞(0)
未经允许不得转载：TI中文支持网 » 关于28035中断嵌套，嵌套的中断多执行了一次
分享到： 更多 (0)
标签：

相关推荐

热门标签

ECTE (3265)#希望得到TI的工程师回答 (1566)C2000WARE (918)DSP (853)希望得到TI工程师回答# (853)盼望能得到TI的人回答 (753)UniFlash (751)TMS320F28335 (750)电源管理 (748)TMS320C6678 (720)【紧急+重要】 (703)技术询问 (691)cc1310 (618)TDA4VM (612)电源 (599)Controlsuite (576)AWR2243 (531)6678 (530)AWR1642 (516)电池管理 (495)【紧急】+重要 (492)sysbios (486)AM5728 (486)CC2640R2F (448)AM3352 (446)#DCA1000EVM (432)放大器 (417)TMS320C6748 (410)bq40z50 (403)28335 (400)

热门文章