I use the “SwitcherPro Desktop”software to design .
My Vin=23~25 Vout=27V IOUT=0.1A
I have different resistance from 105 mR to 100mR (R13)
MY Loads is double 12v’s battery.
My circuit as below
My Vout will connet to 24v battery to support battery electrify.
When I no connect the battery (NO LOAD).
My Vin is 24V , Vout is 27v ( red wire),Iout is 0A(blue wire) . as below .
It’s OK.
But when I connect the battery . (Connect LOAD)
My Vout from 27 down to 24.4v and the IOUT (OUT CURRENT) have a 1.1A, 1.16ms.
The current ‘s distance about 700mS
As below two photo.
I want to know what’s happen?
How can I let my circuit Vout=27v Iout=0.1A when I connect the load?
Thanks!
Trevor:
Jane,
输出电压为24.4V,输出电流为1.1A,主要是因为所接负载:电池的特性所决定的,TPS40210相当于一个充电器,对
电池进行快速充电。如果希望输出27V 0.1A,可以使用电子负载来验证。
Johnsin Tao:
回复 Trevor:
如果你是要给电池充电,您需要采用电池充电芯片,例如BQ24620: www.ti.com.cn/…/bq24620.pdf,
wu jane:
回复 wei wang1:
謝謝大家的回答!!