TI中文支持网各位计数工程师好：
本人使用2048线的编码器，采用28335计算电机转速，在程序看门狗复位之后，会遇到捕获编码器Z信号（index信号）失败的现象，而编码器A/B信号的捕获是正常的，阅读了TI文档，发现有这的描述
Quadrature encoders from different manufacturers come with two forms of index pulse (gated index pulse or ungated index pulse) as shown in Figure 3. A nonstandard form of index pulse is ungated. In the ungated configuration, the index edges are not necessarily coincident with A and B signals. The gated index pulse is aligned to any of the four quadrature edges and width of the index pulse and can be equal to a quarter, half, or full period of the quadrature signal.
也就是说index信号捕获和时序有关，因为芯片处于 ungated状态了，及截止状态了。所以更改了程序，在检测捕获A、B、Z的IO口电平信号在特定电平的情况下（例如A= 1，B=1，Z=0）才启动eQEP的配置，但是仍然没有解决捕获编码器Z信号（index信号）失败的现象。请问上面的理解正确吗，对于编码器捕获index信号的失败有没有好的解决办法，谢谢！
